SQL | LeetCode 585. 중복된 투자값 & 유일한 위치 조건 만족하는 투자 합계 구하기

Table: Insurance

+-------------+-------+
| Column Name | Type  |
+-------------+-------+
| pid         | int   |
| tiv_2015    | float |
| tiv_2016    | float |
| lat         | float |
| lon         | float |
+-------------+-------+
pid is the primary key (column with unique values) for this table.
Each row of this table contains information about one policy where:
pid is the policyholder's policy ID.
tiv_2015 is the total investment value in 2015 and tiv_2016 is the total investment value in 2016.
lat is the latitude of the policy holder's city. It's guaranteed that lat is not NULL.
lon is the longitude of the policy holder's city. It's guaranteed that lon is not NULL.

 

Write a solution to report the sum of all total investment values in 2016 tiv_2016, for all policyholders who:

• have the same tiv_2015 value as one or more other policyholders, and
• are not located in the same city as any other policyholder (i.e., the (lat, lon) attribute pairs must be unique).

Round tiv_2016 to two decimal places.

The result format is in the following example.

 

Example 1:

Input: 
Insurance table:
+-----+----------+----------+-----+-----+
| pid | tiv_2015 | tiv_2016 | lat | lon |
+-----+----------+----------+-----+-----+
| 1   | 10       | 5        | 10  | 10  |
| 2   | 20       | 20       | 20  | 20  |
| 3   | 10       | 30       | 20  | 20  |
| 4   | 10       | 40       | 40  | 40  |
+-----+----------+----------+-----+-----+
Output: 
+----------+
| tiv_2016 |
+----------+
| 45.00    |
+----------+
Explanation: 
The first record in the table, like the last record, meets both of the two criteria.
The tiv_2015 value 10 is the same as the third and fourth records, and its location is unique.

The second record does not meet any of the two criteria. Its tiv_2015 is not like any other policyholders and its location is the same as the third record, which makes the third record fail, too.
So, the result is the sum of tiv_2016 of the first and last record, which is 45.

다음 조건을 모두 만족하는 레코드의 tiv_2016 합계를 구하고 싶습니다.

1. tiv_2015 값이 다른 사람과 중복됨
2. (lat, lon) 위치가 다른 사람과 겹치지 않음

SELECT tiv_2015
FROM Insurance
GROUP BY tiv_2015
HAVING COUNT(*) > 1

• 중복된 tiv_2015 값만 골라냄

SELECT lat, lon
FROM Insurance
GROUP BY lat, lon
HAVING COUNT(*) = 1

• (lat, lon) 위치가 유일한 조합만 추출

WHERE tiv_2015 IN (...) AND (lat, lon) IN (...)

• tiv_2015가 중복되면서
• 위치는 유일한 것만 선택

select round(sum(tiv_2016), 2) as tiv_2016 from insurance where tiv_2015 in 
(select tiv_2015 from insurance group by tiv_2015 having count(tiv_2015) > 1)
and (lat, lon) in
(select lat, lon from insurance group by lat, lon having count(*) = 1)